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Stoichiometry and Limiting Reagent

conceptmedium~42 min study9 MCQ

A balanced equation fixes the mole ratio of reactants and products, and the limiting reagent is the one that is consumed first.

What is Stoichiometry and Limiting Reagent?

A balanced equation fixes the mole ratio of reactants and products, and the limiting reagent is the one that is consumed first.

Key formula / rule: Balance the equation before any ratio is used.

Key points

  • Compute the limiting reagent for a given set of reactant amounts.
  • Apply stoichiometry to determine theoretical and percentage yield.

Common exam trap

Choosing the reagent with the smaller mass as limiting.

Definitions

Term

Stoichiometry and Limiting Reagent

Meaning

A balanced equation fixes the mole ratio of reactants and products, and the limiting reagent is the one that is consumed first.

Term

Stoichiometry and Limiting Reagent — explanation

Meaning

Comparing available moles against the required ratio identifies which reactant runs out. Yield is then computed from that reagent alone, with the excess reagent left over.

Learning objectives

  • Compute the limiting reagent for a given set of reactant amounts.

  • Apply stoichiometry to determine theoretical and percentage yield.

Formulae

Key point

Balance the equation before any ratio is used.

Key point

Divide available moles by stoichiometric coefficients to find the limiting reagent.

Key point

Percentage yield is actual divided by theoretical yield × 100.

Prerequisites

  • CHE-U1-BC-T1-S1-C1

Common mistakes

  • Choosing the reagent with the smaller mass as limiting.

  • Computing yield from the excess reagent.

Keywords

  • Stoichiometry

  • Limiting

  • Reagent

Practice preview

  • In the reaction 2H2(g) + O2(g) -> 2H2O(l), if 4 moles of H2 and 3 moles of O2 are mixed and allowed to react, which reactant is the limiting reagent?

    easy

  • Which of the following statements correctly defines a limiting reagent in a chemical reaction?

    easy

  • Methane (CH4) burns in oxygen according to the equation: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g). If 10 L of CH4 reacts with 30 L of O2 at the same temperature and pressure, what is the total volume of gaseous products forme

    medium