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Distance and Family of Lines

conceptmedium~40 min study9 MCQ

The distance from a point to ax + by + c = 0 is |ax0 + by0 + c| / √(a2 + b2), and any line through the intersection of two lines is a linear combination of them.

What is Distance and Family of Lines?

The distance from a point to ax + by + c = 0 is |ax0 + by0 + c| / √(a2 + b2), and any line through the intersection of two lines is a linear combination of them.

Key formula / rule: Distance between parallel lines uses the same formula with matched coefficients.

Key points

  • Compute the perpendicular distance from a point to a line.
  • Apply the family-of-lines method to concurrency problems.

Common exam trap

Forgetting the absolute value and reporting a negative distance.

Definitions

Term

Distance and Family of Lines

Meaning

The distance from a point to ax + by + c = 0 is |ax0 + by0 + c| / √(a2 + b2), and any line through the intersection of two lines is a linear combination of them.

Term

Distance and Family of Lines — explanation

Meaning

The distance formula converts geometric conditions into algebra, while the family-of-lines idea removes the need to compute intersection points explicitly.

Learning objectives

  • Compute the perpendicular distance from a point to a line.

  • Apply the family-of-lines method to concurrency problems.

Formulae

Key point

Distance between parallel lines uses the same formula with matched coefficients.

Key point

L1 + k L2 = 0 represents the family through the intersection of L1 and L2.

Key point

The angle bisectors of two lines are found by equating the distance expressions.

Prerequisites

  • MAT-U3-SL-T1-S1-C1

Common mistakes

  • Forgetting the absolute value and reporting a negative distance.

  • Using the family formula with unmatched coefficient normalisation.

Keywords

  • Distance

  • Family

  • Lines

Practice preview

  • The equation of the line passing through the intersection of the lines 2x + 3y - 4 = 0 and x - 5y + 7 = 0 and also passing through the point (2, 1) is:

    easy

  • Find the value of 'k' such that the point (1, 2) is equidistant from the lines 3x + 4y - 1 = 0 and 8x + 6y - k = 0.

    medium

  • A point on the line x + y = 4 which is at a unit distance from the line 4x + 3y - 10 = 0 is:

    medium