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Concept of Centre of Mass

subtopiceasy~15 min study15 MCQ

Understanding the definition and physical significance of the centre of mass for a system of particles.

Practice 10 questionsBack to syllabus~15 min · 15 questions in the bank

What is Concept of Centre of Mass?

The unique point in a system of particles or a body where the weighted average position of all the mass is located. It is the point at which the system would balance if it were pivoted there.

Key formula / rule: Position Vector of Centre of Mass (Discrete System)

Key points

  • Define the centre of mass for a system of particles.
  • Calculate the position vector of the centre of mass.
  • Understand the physical significance of the centre of mass.
  • Analyze the motion of the centre of mass under external forces.

Common exam trap

Confusing centre of mass with the geometric centre for non-uniform objects.

Definitions

Term

Centre of Mass (CM)

Meaning

The unique point in a system of particles or a body where the weighted average position of all the mass is located. It is the point at which the system would balance if it were pivoted there.

Term

System of Particles

Meaning

A collection of discrete particles, each with its own mass and position, considered together as a single entity for analysis.

Term

Translational Motion

Meaning

Motion in which all points of a body move in the same direction and at the same speed. The centre of mass describes the translational motion of the entire system.

Learning objectives

  • Define the centre of mass for a system of particles.

  • Calculate the position vector of the centre of mass.

  • Understand the physical significance of the centre of mass.

  • Analyze the motion of the centre of mass under external forces.

Formulae

Name

Position Vector of Centre of Mass (Discrete System)

Note

Where mᵢ is the mass of the i-th particle and rᵢ is its position vector. M is the total mass of the system.

Expression

\vec{R}_{CM} = \frac{\sumi=1^{n} mi \vec{r}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{r}_i

Name

Velocity of Centre of Mass (Discrete System)

Note

Where vᵢ is the velocity of the i-th particle.

Expression

\vec{V}_{CM} = \frac{d\vec{R}_{CM}}{dt} = \frac{\sumi=1^{n} mi \vec{v}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{v}_i

Name

Acceleration of Centre of Mass (Discrete System)

Note

Where aᵢ is the acceleration of the i-th particle. Using Newton's second law (Fᵢ = mᵢaᵢ), A<0xE2><0x82><0x9C><0xE1><0xB5><0x80> = (Σ Fᵢ) / M = F<0xE2><0x82><0x91><0xE2><0x82><0x99><0xE1><0xB5><0x9C> / M.

Expression

\vec{A}_{CM} = \frac{d\vec{V}_{CM}}{dt} = \frac{\sumi=1^{n} mi \vec{a}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{a}_i

Name

Centre of Mass (Continuous Body)

Note

Where dm is an infinitesimal mass element and r is its position vector. Integration is performed over the entire body.

Expression

\vec{R}_{CM} = \frac{\int \vec{r} dm}{\int dm} = \frac{1}{M} \int \vec{r} dm

Prerequisites

  • Understanding of vectors (position, displacement).

  • Basic concepts of mass and density.

  • Familiarity with summation notation.

Common mistakes

  • Confusing centre of mass with the geometric centre for non-uniform objects.

  • Ignoring the vector nature of position and velocity of the CM.

  • Assuming the CM is always within the physical boundaries of the object.

  • Incorrectly calculating the weighted average when masses or positions are not properly considered.

Keywords

  • Centre of Mass

  • System of Particles

  • Weighted Average

  • Translational Motion

  • Rigid Body Dynamics

  • Momentum Conservation

  • Newton's Laws

Practice preview

  • For a system of two particles of masses m1 and m2, separated by a distance r, the centre of mass is located at a distance from m1 given by:

    medium

  • If a system consists of only two particles, the centre of mass:

    easy

  • If a body is acted upon by no external force, then the centre of mass:

    medium