Concept of Centre of Mass
Understanding the definition and physical significance of the centre of mass for a system of particles.
What is Concept of Centre of Mass?
The unique point in a system of particles or a body where the weighted average position of all the mass is located. It is the point at which the system would balance if it were pivoted there.
Key formula / rule: Position Vector of Centre of Mass (Discrete System)
Key points
- Define the centre of mass for a system of particles.
- Calculate the position vector of the centre of mass.
- Understand the physical significance of the centre of mass.
- Analyze the motion of the centre of mass under external forces.
Common exam trap
Confusing centre of mass with the geometric centre for non-uniform objects.
Definitions
- Term
Centre of Mass (CM)
- Meaning
The unique point in a system of particles or a body where the weighted average position of all the mass is located. It is the point at which the system would balance if it were pivoted there.
- Term
System of Particles
- Meaning
A collection of discrete particles, each with its own mass and position, considered together as a single entity for analysis.
- Term
Translational Motion
- Meaning
Motion in which all points of a body move in the same direction and at the same speed. The centre of mass describes the translational motion of the entire system.
Learning objectives
Define the centre of mass for a system of particles.
Calculate the position vector of the centre of mass.
Understand the physical significance of the centre of mass.
Analyze the motion of the centre of mass under external forces.
Formulae
- Name
Position Vector of Centre of Mass (Discrete System)
- Note
Where mᵢ is the mass of the i-th particle and rᵢ is its position vector. M is the total mass of the system.
- Expression
\vec{R}_{CM} = \frac{\sumi=1^{n} mi \vec{r}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{r}_i
- Name
Velocity of Centre of Mass (Discrete System)
- Note
Where vᵢ is the velocity of the i-th particle.
- Expression
\vec{V}_{CM} = \frac{d\vec{R}_{CM}}{dt} = \frac{\sumi=1^{n} mi \vec{v}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{v}_i
- Name
Acceleration of Centre of Mass (Discrete System)
- Note
Where aᵢ is the acceleration of the i-th particle. Using Newton's second law (Fᵢ = mᵢaᵢ), A<0xE2><0x82><0x9C><0xE1><0xB5><0x80> = (Σ Fᵢ) / M = F<0xE2><0x82><0x91><0xE2><0x82><0x99><0xE1><0xB5><0x9C> / M.
- Expression
\vec{A}_{CM} = \frac{d\vec{V}_{CM}}{dt} = \frac{\sumi=1^{n} mi \vec{a}_i}{\sumi=1^{n} mi} = \frac{1}{M} \sumi=1^{n} mi \vec{a}_i
- Name
Centre of Mass (Continuous Body)
- Note
Where dm is an infinitesimal mass element and r is its position vector. Integration is performed over the entire body.
- Expression
\vec{R}_{CM} = \frac{\int \vec{r} dm}{\int dm} = \frac{1}{M} \int \vec{r} dm
Prerequisites
Understanding of vectors (position, displacement).
Basic concepts of mass and density.
Familiarity with summation notation.
Common mistakes
Confusing centre of mass with the geometric centre for non-uniform objects.
Ignoring the vector nature of position and velocity of the CM.
Assuming the CM is always within the physical boundaries of the object.
Incorrectly calculating the weighted average when masses or positions are not properly considered.
Keywords
Centre of Mass
System of Particles
Weighted Average
Translational Motion
Rigid Body Dynamics
Momentum Conservation
Newton's Laws
Practice preview
For a system of two particles of masses m1 and m2, separated by a distance r, the centre of mass is located at a distance from m1 given by:…
medium
If a system consists of only two particles, the centre of mass:…
easy
If a body is acted upon by no external force, then the centre of mass:…
medium
