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Equilibrium Constant in Gaseous Systems (Kp)

subtopicmedium~25 min study33 MCQ

Formulating and calculating the equilibrium constant in terms of partial pressures for gaseous reactions.

Practice 10 questionsBack to syllabus~15 min · 33 questions in the bank

What is Equilibrium Constant in Gaseous Systems (Kp)?

The equilibrium constant expressed in terms of the partial pressures of the gaseous components involved in a reversible reaction.

Key formula / rule: Kp Expression

Key points

  • Define and write the expression for Kp for a given gaseous reaction.
  • Calculate Kp using partial pressures at equilibrium.
  • Relate Kp to Kc.
  • Interpret the significance of Kp value.

Common exam trap

Forgetting to use partial pressures instead of total pressures.

Definitions

Term

Kp

Meaning

The equilibrium constant expressed in terms of the partial pressures of the gaseous components involved in a reversible reaction.

Term

Partial Pressure

Meaning

The pressure exerted by a single component gas in a mixture of gases, as if it were the only gas present in the container.

Term

Δn

Meaning

The change in the number of moles of gaseous products minus the number of moles of gaseous reactants in a balanced chemical equation.

Learning objectives

  • Define and write the expression for Kp for a given gaseous reaction.

  • Calculate Kp using partial pressures at equilibrium.

  • Relate Kp to Kc.

  • Interpret the significance of Kp value.

Formulae

Name

Kp Expression

Note

For aA(g) + bB(g) ⇌ cC(g) + dD(g)

Expression

Kp = (pCc * pDd) / (pAa * pBb)

Name

Partial Pressure

Note

where pi is partial pressure, xi is mole fraction, Ptotal is total pressure.

Expression

pi = xi * Ptotal

Name

Relationship between Kp and Kc

Note

R is the universal gas constant, T is absolute temperature in Kelvin, Δn = (sum of stoichiometric coefficients of gaseous products) - (sum of stoichiometric coefficients of gaseous reactants).

Expression

Kp = Kc(RT)^Δn

Prerequisites

  • Understanding of chemical equilibrium.

  • Concept of reversible reactions.

  • Partial pressures and mole fractions.

  • Stoichiometry.

Common mistakes

  • Forgetting to use partial pressures instead of total pressures.

  • Incorrectly calculating the stoichiometric coefficients (Δn).

  • Including solids or liquids in the Kp expression (they are omitted).

  • Confusing Kp with Kc without considering the units or Δn.

Keywords

  • Kp

  • Equilibrium Constant

  • Gaseous Systems

  • Partial Pressure

  • Stoichiometric Coefficients

  • Δn

  • Kc

  • Chemical Equilibrium

Practice preview

  • In a 10 L vessel, 2 moles of SO2 and 1 mole of O2 are introduced. At equilibrium, 1 mole of SO3 is formed. If the total pressure at equilibrium is 4 atm and the temperature is 300 K, what is the value of Kp for the react

    hard

  • What is the correct expression for Kp for the reaction 2NO(g) + O2(g) <=> 2NO2(g)?

    easy

  • For the heterogeneous equilibrium CaCO3(s) <=> CaO(s) + CO2(g), the expression for Kp is:

    medium